y^2-68y+256=0

Solution for y^2-68y+256=0 equation:

y^2-68y+256=0

a = 1; b = -68; c = +256;
Δ = b2-4ac
Δ = -682-4·1·256
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-60}{2*1}=\frac{8}{2}
=4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+60}{2*1}=\frac{128}{2}
=64
$